the heat generated in 5ohm resistorbdue to current flowing through ot is 10cal
Answer (1)
Student Expert
13th Oct, 2019
Hello there!
Greetings!
Though you haven't completed your question, I got your doubt and is providing you the solution.
We know that , H = I^2Rt
Here R is resistance, I is current, H is the heat and t is time.
Given data:
R1 = 5ohm
H = 10 calories
R2 = 4ohm
Time, t = 1 second
For resistance R1, H= I^2RT
10 = I2 X 5 ohm x1s
I2= 2
Now for resistance R2:
H = I^2Rt
H = 2 X 4 X 1
H=8 calorie
Thankyou
Greetings!
Though you haven't completed your question, I got your doubt and is providing you the solution.
We know that , H = I^2Rt
Here R is resistance, I is current, H is the heat and t is time.
Given data:
R1 = 5ohm
H = 10 calories
R2 = 4ohm
Time, t = 1 second
For resistance R1, H= I^2RT
10 = I2 X 5 ohm x1s
I2= 2
Now for resistance R2:
H = I^2Rt
H = 2 X 4 X 1
H=8 calorie
Thankyou
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