Question : The height of a cylinder is 45 cm. If the circumference of its base is 132 cm, then what is the curved surface of this cylinder? (use $\pi=\frac{22}{7}$)
Option 1: 6360 cm2
Option 2: 6270 cm2
Option 3: 5720 cm2
Option 4: 5940 cm2
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Correct Answer: 5940 cm 2
Solution :
Given: The height of a cylinder is 45 cm.
The circumference of the base of the cylinder = $2\pi r$
The curved surface of the cylinder = $2\pi rh$
Where $r$ and $h$ are the radius and height.
The circumference of its base is 132 cm.
⇒ $2\times \frac{22}{7}\times r=132$
⇒ $r=21$ cm
The curved surface of the cylinder = $2\times \frac{22}{7} \times 21\times 45=44 \times 135=5940$ cm
2
Hence, the correct answer is 5940 cm
2
.
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