Question : The income of A is 10% more than the income of B. Let B's income be $x$% less than A's income. Find $x$.
Option 1: $9\frac{1}{11}$%
Option 2: $10\frac{1}{11}$%
Option 3: $11$%
Option 4: $10$%
Correct Answer: $9\frac{1}{11}$%
Solution :
Given: The income of A is 10% more than the income of B. Let B's income be $x$% less than A's income.
Let the income of B be 100 units.
So, the income of A = (100 + 10) = 110 units
B's income is $x$% less than A's income.
Therefore, less percentage $x=\frac{10}{110}×100=\frac{100}{11}=9\frac{1}{11}$%.
Hence, the correct answer is $9\frac{1}{11}$%.
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