Question : The internal length, breadth, and height of a cuboidal room are 12 m, 8 m, and 10 m, respectively. The total cost (in INR) of whitewashing only all four walls of the room at the cost of INR 25 per m2, is:
Option 1: 12,600
Option 2: 10,000
Option 3: 11,400
Option 4: 18,000
Correct Answer: 10,000
Solution : Length = 12 m Breadth = 8 m Height = 10 m Cost of 1 m$^2$ wall painting = INR 25 Formula used: Area of four walls = 2(l + b) × h Where, Length = l Breadth = b Height = h Calculation: Area of four walls = 2(l + b) × h = 2(12 + 8) × 10 = 2 × 20 × 10 = 400 m$^2$ Cost of 1 m$^2$ wall painting = INR 25 Cost of 400 m$^2$ wall painting = INR 25 × 400 = INR 10,000 $\therefore$ Total cost (in INR) of whitewashing only all four walls of the room is INR 10,000. Hence, the correct answer is 10,000.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : A cuboidal room's internal measures are a length of 12 m, a breadth of 8 m, and a height of 10 m. The total cost (in INR ) of whitewashing all four walls of the room and also the ceiling of the room, if the cost of whitewashing is INR 25 per m2 is:
Question : The internal length of a room is two times its breadth and three times its height. The total cost of painting its four walls at the rate of INR 25/m2 is INR 3,600. What is the cost of laying a carpet on its floor at the rate of INR 90.50/m2?
Question : The length and breadth of a cuboidal store are in the ratio 2 : 1 and its height is 3.5 metres. If the area of its four walls (including doors) is 210 m2, its volume is ____.
Question : The length of cold storage is 5 times its breadth, and its height is 8 m. The area of its four walls (including the doors) is 720 m2. Find the total surface area of cold storage.
Question : What is the total surface area of a cuboid whose length, breadth, and height are 7 cm, 5 cm, and 9 cm, respectively?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile