Question : The least number among $\frac{4}{9}, \sqrt{\frac{9}{49}}, 0.45$ and $(0.8)^{2}$:
Option 1: $\frac{4}{9}$
Option 2: $\sqrt{\frac{9}{49}}$
Option 3: $0.45$
Option 4: $(0.8)^{2}$
Correct Answer: $\sqrt{\frac{9}{49}}$
Solution :
Decimal value of given numbers:
$ ⇒ \frac{4}{9} = 0.44$
$ ⇒ \sqrt{\frac{9}{49}} = \frac{3}{7} = 0.43$
$ ⇒ 0.45$
$ ⇒ (0.8)^{2} = 0.64$
By comparing these values, we get:
The least number = $\sqrt{\frac{9}{49}}$
Hence, the correct answer is $\sqrt{\frac{9}{49}}$.
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