Question : The least number that must be subtracted from 1294 such that the obtained number when divided by 9, 11, and 13, leaves in each case the same remainder of 6, is:
Option 1: 2
Option 2: 3
Option 3: 1
Option 4: 4
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Correct Answer: 1
Solution :
The LCM of 9, 11, and 13 is 1287.
When 1294 is divided by 1287, the quotient is 1 and the remainder is 7.
Here, we need the remainder in each case to be 6 and so, subtract (7 – 6) = 1 from 1294.
Hence, the correct answer is 1.
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