Question : The least value of $\tan^2x+\cot^2x$ is:
Option 1: 3
Option 2: 2
Option 3: 0
Option 4: 1
Answer (1)
18th Jan, 2024
Correct Answer: 2
Solution :
The value will be minimum when $x = 45°$
Minimum value $= \tan^2x+\cot^2x=\tan^245°+\cot^245°=1+1=2$
Hence, the correct answer is 2.
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