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Question : The least value of $\tan^2x+\cot^2x$ is:

Option 1: 3

Option 2: 2

Option 3: 0

Option 4: 1


Team Careers360 12th Jan, 2024
Answer (1)
Team Careers360 18th Jan, 2024

Correct Answer: 2


Solution : The value will be minimum when $x = 45°$
Minimum value $= \tan^2x+\cot^2x=\tan^245°+\cot^245°=1+1=2$
Hence, the correct answer is 2.

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