Question : The length of a cuboid is 8 cm. If the breadth of the cuboid is twice its length and the height of the cuboid is half of its length, then what is the total surface area of the cuboid?
Option 1: $448 \ \text{cm}^2$
Option 2: $216 \ \text{cm}^2$
Option 3: $188\ \text{cm}^2$
Option 4: $154\ \text{cm}^2$
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Correct Answer: $448 \ \text{cm}^2$
Solution : Given: Length, $l$ = 8 cm Breadth, $b$ = 2 × 8 = 16 cm Height, $h$ = $\frac{1}{2}$ × 8 = 4 cm We know that, the total surface area of cuboid = $2(lb + bh + hl)$ = $2(8\times16 + 16\times4 + 4\times8)$ = $2(128 + 64 + 32)$ = $2\times224$ = $448\ \text{cm}^2$ Hence, the correct answer is $448\ \text{cm}^2$.
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