Question : The length of the median of an equilateral triangle is $12\sqrt3 \text{ cm}$. Then, the area of the triangle is:
Option 1: $144\text{ cm}^2$
Option 2: $288\sqrt3\text{ cm}^2$
Option 3: $144\sqrt3\text{ cm}^2$
Option 4: $288\text{ cm}^2$
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Correct Answer: $144\sqrt3\text{ cm}^2$
Solution : Given: The length of the median of an equilateral triangle is $12\sqrt3\text{ cm}$. The height of an equilateral triangle of the side $x$ is $\frac{\sqrt3}{2} x$ and its area is given as $\frac{\sqrt3}{4} x^2$. According to the question, $\frac{\sqrt3}{2} x =12\sqrt3 $ ⇒ $x=24\text{ cm}$ Then, the area of the triangle is given as, $\frac{\sqrt3}{4}\times x^2$ $=\frac{\sqrt3}{4}\times (24)^2$ $=144\sqrt3\text{ cm}^2$ Hence, the correct answer is $144\sqrt3\text{ cm}^2$.
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