Question : The lengths of the diagonals of a rhombus are 24 cm and 10 cm, then the perimeter of the rhombus (in cm) is:
Option 1: 52
Option 2: 56
Option 3: 68
Option 4: 72
Correct Answer: 52
Solution :
Given: The lengths of the diagonals of a rhombus are 24 cm and 10 cm.
So, the length of the sides
= $\sqrt{(\frac{24}{2})^2+(\frac{10}{2})^2}$
= $\sqrt{12^2+5^2}$
= $\sqrt{169}$
= $13$
$\therefore$ The perimeter of the rhombus = (4 × 13) = 52 cm
Hence, the correct answer is 52.
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