Question : The lengths of the diagonals of a rhombus are 48 cm and 20 cm. What is the perimeter of the rhombus?
Option 1: 200 cm
Option 2: 120 cm
Option 3: 100 cm
Option 4: 104 cm
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Correct Answer: 104 cm
Solution : Diagonals of a rhombus bisect each other perpendicularly. Let’s denote the length of each side of the rhombus as a Using Pythagoras: a 2 = $(\frac{48}{2})^{2}$ + $(\frac{20}{2})^{2}$ = 576 + 100 = $\sqrt{676}$ ⇒ a = 26 So, the length of each side is 26 ⇒ Perimeter = 4a = 4 × 26 = 104 cm Hence, the correct answer is 104 cm.
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