Question : The lengths of the two sides adjacent to the right angle of a right-angled triangle are 1.6 cm and 6.3 cm. Find the length of the hypotenuse.
Option 1: 6.7 cm
Option 2: 7.5 cm
Option 3: 6.5 cm
Option 4: 7 cm
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 6.5 cm
Solution : Given, Base = 1.6 cm and Perpendicular = 6.3 cm Applying Pythagoras theorem, we get, $\small\text{Hypotenuse}^2 = \text{Base}^2+\text{Perpendicular}^2$ ⇒ $h^2=(1.6)^2+(6.3)^2$ ⇒ $h^2=2.56+39.69=42.25$ ⇒ $h=\sqrt{42.25}=6.5$ cm Hence, the correct answer is 6.5 cm.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : $\triangle$ LON and $\triangle$ LMN are two right-angled triangles with common hypotenuse LN such that $\angle$ LON = $90^{\circ}$ and $\angle$ LMN = $90^{\circ}$. LN is the bisector of $\angle$ OLM. If LN = 29 cm and ON = 20 cm, then what is the perimeter (in cm) of
Question : The hypotenuse of a right-angled triangle is 39 cm and the difference of the other two sides is 21 cm. Then, the area of the triangle is:
Question : The lengths of the two sides of a triangle are 14 cm and 9 cm. Which of the options below can be the length of the third side?
Question : Let $ABC$ and $PQR$ be two congruent right-angled triangles such that $\angle A=\angle P=90^{\circ}$. If $BC=13\ \text{cm}$ and $PR=12\ \text{cm}$, then find the length of $AB$.
Question : Two similar triangles are given i.e. $\triangle$LMN ~ $\triangle$PQR, with measurement of angle and side as $\angle$ L = 40°, $\angle$ N = 80°, LM = 6 cm, LN = 8 cm and PQ = 7.5 cm. Find the value of $\angle$ Q and side PR, respectively.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile