Question : The lengths of three line segments are given. Is the construction of a triangle possible with the segments in the given cases?
Option 1: 8 cm, 7 cm, 18 cm
Option 2: 8 cm, 15 cm, 17 cm
Option 3: 10 cm, 6 cm, 4 cm
Option 4: 8 cm, 10 cm, 20 cm
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Correct Answer: 8 cm, 15 cm, 17 cm
Solution : As we know the sum of two sides of a triangle is greater than the third side. Clearly, (8 + 15) > 17 (15 + 17) > 8 (8 + 17) > 15 Therefore, the triangle's possible sides are 8 cm, 15 cm, and 17 cm. Hence, the correct answer is '8 cm, 15 cm, 17 cm'.
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Question : Which of the set of three sides can't form a triangle?
Question : Possible lengths of the three sides of a triangle are:
Question : In $\triangle \mathrm{ABC}$, $AB=20$ cm, $BC=7$ cm and $CA=15$ cm. Side $BC$ is produced to $D$ such that $\triangle \mathrm{DAB} \sim \triangle \mathrm{DCA}$. $DC$ is equal to:
Question : Which of the following sets of lengths (in cm) will give three sides of an obtuse-angled triangle?
Question : The lengths of the three medians of a triangle are $9\;\mathrm{cm}$, $12\;\mathrm{cm}$, and $15\;\mathrm{cm}$. The area (in $\mathrm{cm^2}$) of the triangle is:
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