Question : The liquids, X and Y are mixed in the ratio of 3 : 2 and the mixture is sold at Rs. 11/litre at a profit of 10%. If the liquid X costs Rs. 2 more per litre than Y, the cost of X /litre is (in Rs.):
Option 1: 10.80
Option 2: 11.75
Option 3: 9.50
Option 4: 11
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Correct Answer: 10.80
Solution : Given: X and Y are mixed in the ratio of 3 : 2. The mixture is sold at Rs. 11/litre at a profit of 10%. Liquid X costs Rs. 2 more per litre than Y. At 10% profit the selling price(SP) of the mixture $=$ Rs. 11 So, the cost price(CP) of the mixture $=$ $\frac{11}{110}$ × 100 $=$ Rs. 10 Let the cost of liquid X $=$ Rs. $x$ per litre So, the cost of liquid Y $=$ Rs. $(x-2)$ per litre Cost of 5 litres of the mixture $=$ $3x+2(x-2)$ According to the question, $3x+2(x-2)=5×10$ ⇒ $3x+2x-4=50$ ⇒ $5x=54$ ⇒ $x=\frac{54}{5}$ ⇒ $x=$ Rs. 10.80/litre Hence, the correct answer is 10.80.
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