Question : The longest side of the obtuse triangle is 7 cm and the other two sides of the triangle are 4 cm and 5 cm. Find the area of the triangle.
Option 1: $1 \sqrt{3} \mathrm{~cm}^2$
Option 2: $6 \sqrt{3} \mathrm{~cm}^2$
Option 3: $3 \sqrt{2} \mathrm{~cm}^2$
Option 4: $4 \sqrt{6} \mathrm{~cm}^2$
New: SSC MTS Tier 1 Answer key 2024 out
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $4 \sqrt{6} \mathrm{~cm}^2$
Solution : Given triangle is an obtuse triangle as $7^2 > 4^2 + 5^2$. Semi perimeter of the triangle($s$) = $\frac{7+4+5}{2}$ = 8 cm $\therefore$ Area of the triangle = $\sqrt{8(8-7)(8-4)(8-5)}$ = $\sqrt{8×(1)×(4)×(3)}$ = $\sqrt{96}$ = $\sqrt{16×6}$ = $4\sqrt{6} \mathrm{~cm}^2$ Hence, the correct answer is $4 \sqrt{6} \mathrm{~cm}^2$.
Answer Key | Cutoff | Selection Process | Preparation Tips | Eligibility | Application | Exam Pattern
Question : If $\triangle \mathrm{ABC}$ is similar to $\triangle \mathrm{DEF}$ such that $\mathrm{BC}=3 \mathrm{~cm}, \mathrm{EF}=4 \mathrm{~cm}$ and the area of $\triangle \mathrm{ABC}=54 \mathrm{~cm}^2$, then the area of $\triangle \mathrm{DEF}$ is:
Question : The area of a square is 144 cm2. What is the length of each of its diagonals?
Question : The ratio of the sides of a triangle is 3 : 3 : 4. If the area of a triangle is $32 \sqrt{5}$ cm2, then what is the length of the equal sides?
Question : The ratio of the sides of a triangle is 11 : 11 : 4. If the area of the triangle is $2\sqrt{117}$ cm, then what is the length of the equal sides?
Question : If the area of a square is 529 cm2, then what is the length of its diagonal?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile