The magnitude of scalar product of two vector is 8 and that of vector product is 8 root 3 the angle beyween them is
Answers (2)
21st Jun, 2018
It is a simple question. Let's consider two equations first for the scalar product second for the vector product. Let the angle be t.
Scalar product = a.b.cos t = 8
Vector product = a.b.sin t = 8 root 3
Dividing second equation by first equation we get, sin t/cos t = root 3
We know sin t/cos t = tan t.
So, tan t = root 3 ; and that is the case when angle = 60 degree.
So, t(angle)=60 degree.
Comments (0)
15th Jun, 2018
Hey Jayesh,
The solution is very simple
since, ab=8
absinD=8root3
therefore, 8sinD=8root3
sinD=root3
This is impossible
since, -1<=sinx<=+1
So i think vector product should be 4root3.
Hope this helps you!
Comments (0)
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