the maximum work done in expending 16g
Answer (1)
Student Expert
6th Oct, 2019
The formula for calculating maximum work done (reversible work) is
W = -2.303*n*R*T*log(V2/V1)
RT= 8.314*300
Calculating n , given 16g of oxygen
n= (Given amount of oxygen)/(Molecular mass of Oxygen, O2)
n= 16/32 =
0.5
and, according to the question
V2 = 25 dm3
V1 = 5 dm3
Putting all the values in work done equation we get,
W = 2.303*(0.5)*8.314*300*log(25/5)
W = 2.01 x 10^3 Joule
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