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The mimimum value of x2+7x-5 is m at x=lambda then m +lambda


kasinineetha 16th Nov, 2020
Answer (1)
anshika.verma2019 16th Nov, 2020

Dear Aspirant,

x 2 + 7x – 5

Minimum at x= Lambda

Let the given equation equals Y

Thus, Y = x 2 + 7x - 5

dY/dx

=d(x 2 + 7x - 5)/dx

= 2x + 7

Put it equal to 0

2x + 7 = 0

x = -7/2

Now, take perform double differentiation of Y.

= d(2x + 7)/dx

= 2

Since the value is positive.

Hence, we will get the minimum value at x = -7/2.

So, Lambda = -7/2

At x = -7/2, Y = m.

Thus, (-7/2) 2 + 7(-7/2) – 5

= 49/4 – 49/2 – 5

= - 49/4 – 5

= - 69/4

Thus, m = -69/4

Hope your doubt is solved

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