The mimimum value of x2+7x-5 is m at x=lambda then m +lambda
Answer (1)
16th Nov, 2020
Dear Aspirant,
x 2 + 7x – 5
Minimum at x= Lambda
Let the given equation equals Y
Thus, Y = x 2 + 7x - 5
dY/dx
=d(x 2 + 7x - 5)/dx
= 2x + 7
Put it equal to 0
2x + 7 = 0
x = -7/2
Now, take perform double differentiation of Y.
= d(2x + 7)/dx
= 2
Since the value is positive.
Hence, we will get the minimum value at x = -7/2.
So, Lambda = -7/2
At x = -7/2, Y = m.
Thus, (-7/2) 2 + 7(-7/2) – 5
= 49/4 – 49/2 – 5
= - 49/4 – 5
= - 69/4
Thus, m = -69/4
Hope your doubt is solved
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