Question : The monthly expenses of a person are $66 \frac{2}{3} \%$ more than her monthly savings. If her monthly income increases by 44% and her monthly expenses increase by 60%, then there is an increase of INR 1,040 in her monthly savings. What is the initial expenditure (in INR)?
Option 1: 10,000
Option 2: 12,000
Option 3: 13,000
Option 4: 9,000
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Correct Answer: 10,000
Solution : The monthly expenses is $66\frac{2}{3}$% more than her monthly savings. $66\frac{2}{3}\% = \frac{2}{3}$ So, The monthly expenses = The monthly savings + (The monthly saving) × $\frac{2}{3}$ The monthly expenses = (The monthly saving) × $\frac{5}{3}$ Let the monthly saving = $3x$ and the monthly expenditure = $5x$ The monthly income = $(5x + 3x) = 8x$ Now, Her monthly income increases = 44% = $8x \times \frac{144}{100}$ = $\frac{1152x}{100}$ = $11.52x$ Now, Her monthly expenses increases = 60% = $5x \times \frac{160}{100}$ = $\frac{800x}{100}$ = $8x$ The savings of the person = $(11.52x - 8x) = 3.52x$ According to the question, There is an increase in her monthly savings = INR 1040 ⇒ $(3.52x - 3x) = 1040$ ⇒ $0.52x = 1040$ ⇒ $x = \frac{1040}{0.52}$ ⇒ $x = 2000$ Now, The initial expenditure = $5x = 5 \times 2000= 10000$ Hence, the correct answer is INR 10,000.
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