the number of electrons present in 3.2grams of oxygen gas Is?
Answer (1)
24th Jan, 2021
Hello there,
As there is the case of oxygen gas, means we have O2. Firstly we calculate the number of moles in 3.2 g of this gas.
no. of moles = given mass / molar mass
= 3.2/32 = 0.1moles
Now we calculate the total number of molecules in this amount of O2.
= 0.1 * 6.022 * 10^(23)
Now we know that, one molecule of O2 has 2 atoms of oxygen and 1 atom of oxygen contains 8 electrons. So total no of electrons in 2 atoms/1 molecule are 16.
For total no of electrons in 3.2 g O2 are =
6.022 * 10^(22) * 16
Hope it helps.
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