The number of real roots of the equation x^2-3x +2=0 is ?
Answer (1)
22nd Oct, 2018
First, we will calculate Discriminant:
D=b^2-4ac
Here a=1,b=-3,c=2
therefore D=(-3)^2-4*1*2
D=9-8
D=1
Since Discriminant is greater than zero it means two real and discrete roots.
Now the roots are 3+1/2 and 3-1/2
That is the roots of the given equation are 2 and 1
That is equation has two real roots.
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