83 Views

The number of real roots of the equation x^2-3x +2=0 is ?


tiwaripragati0809 21st Oct, 2018
Answer (1)
Vikas gehlot 22nd Oct, 2018

First, we will calculate Discriminant:

D=b^2-4ac

Here a=1,b=-3,c=2

therefore D=(-3)^2-4*1*2

D=9-8

D=1

Since Discriminant is greater than zero it means two real and discrete roots.

Now the roots are    3+1/2 and 3-1/2

That is the roots of the given equation are 2 and 1

That is equation has two real roots.

Related Questions

Woxsen University B.Sc. Admis...
Apply
Build Your Own Degree - Choose any 3 out of 8 Electives | 100% Plcament track | 100+ Global Partners | 200+ Industry Interactions
Symbiosis School for Liberal ...
Apply
Admissions open for BA/BSc. Liberal Arts (Honours) & BA / BSc. Liberal Arts (Honors) with Research
UPES B.Sc Admissions 2025
Apply
Ranked #46 amongst Universities in India by NIRF | Ranked #1 in Academic Reputation in India by QS World University Rankings
JSS University Noida Admissio...
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
GMAT™ Exam
Apply
Select test center appointment | Scores valid for 5 Years | Multiple Attempts | Round 2 Closing Soon
MATS University M.sc Admissio...
Apply
Approved by UGC | Merit-based scholarships
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books