Question : The oxidation number of Nickel in K4[Ni(CN)4] is
Option 1: 0
Option 2: +4
Option 3: –4
Option 4: +8
New: SSC MTS Tier 1 Answer key 2024 out
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 0
Solution : The correct option is 0.
The oxidation number of Nickel (Ni) in K 4 [Ni(CN) 4 ] is 0.
Let "x" be the oxidation number of nickel (Ni). To neutralize the overall charge of the compound (which is 0), the sum of the oxidation numbers of all the elements must equal 0 . Therefore: (+4) - 4(x) - 4 = 0
Solving for,
4 - 4x - 4 = 0;
-4x = 0;
x = 0.
So, the oxidation number of nickel (Ni) in K 4 [Ni(CN) 4 ] is 0.
Answer Key | Cutoff | Selection Process | Preparation Tips | Eligibility | Application | Exam Pattern
Question : Directions: In the following question, select the one which is different from the other three alternatives.
Question : Directions: In the following question, select the one different from the other three alternatives.
Question : Directions: In the following question, select the missing number of the given series. 50, 39, 27, 14, 0, ?
Question : What is the value of 13 × 12 ÷ 26 – 5 × 24 ÷ 10 + 4 × 4 – 8?
Question : Directions: Some equations are solved based on a certain system. Find the correct answer for the unsolved equation on that basis. 7 – 4 – 1 = 741, 9 – 2 – 3 = 923, 8 –
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile