Question : The perimeter of an equilateral triangle is 48 cm. Find its area (in cm2).
Option 1: $81\sqrt{3}$
Option 2: $8\sqrt{3}$
Option 3: $25\sqrt{3}$
Option 4: $64\sqrt{3}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $64\sqrt{3}$
Solution : Let $a$ be the side of an equilateral triangle. The perimeter of an equilateral triangle = 48 cm So, $3a= 48$ $\therefore a= 16$ Now, the area of an equilateral triangle = $\frac{\sqrt3a^2}{4}$ = $\frac{\sqrt3×16^2}{4}$ = $64\sqrt3$ cm 2 Hence, the correct answer is $64\sqrt3$.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The height of an equilateral triangle is $7 \sqrt{3}$ cm. What is the area of this equilateral triangle?
Question : If the side of an equilateral triangle is 16 cm, then what is its area?
Question : The area of a triangle is 96 cm2 and the ratio of its sides is 6 : 8 : 10. What is the perimeter of the triangle?
Question : If the side of an equilateral triangle is 8 cm, then find the area of the triangle (correct to two decimal places).
Question : The height of an equilateral triangle is $9 \sqrt{3} \mathrm{~cm}$. What is the area of this equilateral triangle?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile