Question : The perimeter of two similar triangles is 30 cm and 20 cm, respectively. If one side of the first triangle is 9 cm. Determine the corresponding side of the second triangle.
Option 1: 13.5 cm
Option 2: 6 cm
Option 3: 15 cm
Option 4: 5 cm
Correct Answer: 6 cm
Solution : Let $\triangle$ABC and $\triangle$DEF be two similar triangles of perimeters P 1 and P 2 , respectively. Also, let AB = 9 cm, P 1 = 30 cm and P 2 = 20 cm Then, $\frac{AB}{DE}=\frac{BC}{EF}=\frac{AC}{DF}=\frac{P_{1}}{P_{2}}$ [Ratio of corresponding sides of similar triangles is equal to the ratio of their perimeters.] ⇒ $\frac{AB}{DE}=\frac{P_{1}}{P_{2}}$ ⇒ $\frac{9}{DE}=\frac{30}{20}$ ⇒ DE = $\frac{9 \times 20}{30} = 6$ cm $\therefore$ The corresponding side of the second triangle is 6 cm. Hence, the correct answer is 6 cm.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : The perimeter of the triangle is 67 cm. The first side is twice the length of the second side. The third side is 11 cm more than the second side. Find the length of the shortest side of the triangle.
Question : One side of the triangle is 15 cm and the corresponding height is 6 cm, then area of the triangle is:
Question : What is the area of a triangle having a perimeter of 32 cm, one side of 11 cm, and the difference between the other two sides is 5 cm?
Question : The radius of the incircle of a triangle is 2 cm. If the area of the triangle is 6 cm2, then its perimeter is:
Question : The perimeters of two similar triangles are 36 cm and 24 cm, respectively. Find the ratio of their areas.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile