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Question : The pie chart given below shows the production of 6 different factories. The total production of all these 6 factories is 15000. The production of a particular factory is shown as a percent of total production of all these 6 factories.
$J_1$ = The value of average production of factories F3 and F6.
$J_2$ = The difference between the production of factory F1 and F4.

What is the value of ($J_2 – J_1$)?

Option 1: 385

Option 2: 395

Option 3: 375

Option 4: 305


Team Careers360 11th Jan, 2024
Answer (1)
Team Careers360 19th Jan, 2024

Correct Answer: 375


Solution : Total production = 15000
Now let's calculate $J_1$ and $J_2$.
$J_1$ = The value of average production of factories F3 and F6
$J_1$ = $\frac{\text{F3 } + \text{ F6}}{2}$
F3 = 6% of 15000
⇒ F3 = 900
F6 = 5% of 15000
⇒ F6 = 750
$\therefore$ J1 = $\frac{900+750}{2}$
⇒ $J_1$ = $825$
And $J_2$ = The difference between the production of factory F1 and F4.
$J_2$ = F4 $-$ F1
F1 = 20% of 15000
⇒ F1 = 3000
F4 = 28% of 15000
⇒ F4 = 4200
$\therefore$ $J_2$ = 4200 $-$ 3000
⇒ $J_2$ = 1200
Now, we have to find ($J_2 - J_1$)
⇒ $J_2 - J_1$ = $1200 - 825 = 375$
Hence, the correct answer is 375.

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