Question : The population of a city increases compounded by 10% annually. The present population of this city is 1,33,100. What was the population of the city 2 years ago?
Option 1: 1,01,000
Option 2: 1,10,000
Option 3: 1,21,000
Option 4: 1,00,000
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 1,10,000
Solution :
$P=P{_0}×(1+r)^t$
where: $P$ is the present population, $P{_0}$ is the past population, $r$ is the annual growth rate (as a decimal), and $t$ is the number of years.
Given, $P{_0} = 133,100$
$r = 10\%$
We have to find the population 2 years ago ($t=−2$ years)
$133100=P{_0}×(1+\frac{10}{100})^{2}$
$⇒P{_0}=133100×(\frac{11}{10})^{−2}$
$⇒P{_0}=133100×\frac{1}{(\frac{11}{10})^2}$
$⇒P{_0}=133100×\frac{100}{121}$
$⇒P{_0}=1,10,000$
Hence, the correct answer is 1,10,000.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
