Question : The population of a town increases each year by 4% of its total at the beginning of the year. If the population on 1st January 2001 was 500000, what was it on 1st January 2004?
Option 1: 562432
Option 2: 652432
Option 3: 465223
Option 4: 564232
Correct Answer: 562432
Solution : The population after $n$ years can be calculated by using the formula $P(1+\frac{\text{R}}{100})^n$ where $P$ is the initial value, $R$ is the rate and $n$ is the time. The population on 1 st January 2001 was 500000. Population after 3 years $= 500000(1+\frac{4}{100})^3$ $= 500000(1+\frac{1}{25})^3$ $= 500000(\frac{26}{25})^3$ $= 500000 \times \frac{26}{25}\times \frac{26}{25}\times \frac{26}{25}$ $= 562432$ Hence, the correct answer is 562432.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : The population of town B is 300% more than that of town A. For the next two years, the population of A increases by $x$% per year, and that of B decreases by the same percentage per year. After 2 years, if the population of A and B become equal, then the value of $x$ is
Question : What is the HCF of (x6 + 1) and (x4 - 1)?
Question : The total surface area of a regular triangular pyramid with each edge of length 1 cm is:
Question : The population of a city is 3,52,314. It increases annually at the rate of 15% per annum. What was its population 2 years ago?
Question : The value of (1+ sin4 A – cos4 A) cosec2 A is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile