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Question : The population of town B is 300% more than that of town A. For the next two years, the population of A increases by $x$% per year, and that of B decreases by the same percentage per year. After 2 years, if the population of A and B become equal, then the value of $x$ is ________.

Option 1: $30 \frac{2}{3}$

Option 2: $33 \frac{1}{3}$

Option 3: $40$

Option 4: $25$


Team Careers360 25th Jan, 2024
Answer (1)
Team Careers360 27th Jan, 2024

Correct Answer: $33 \frac{1}{3}$


Solution : Given :
The population of town B is 300% more than that of town A.
Let the population of town A be 100.
Then, the population of town B = 400
According to the question,
$100 × \frac{100 + x}{100}×\frac{100 + x}{100}  = 400 × \frac{100 -x}{100} ×\frac{100 -x}{100}$ 
$\Rightarrow (100\ +\ x)^2\ =\ 4(100\ -\ x)^2$
$\Rightarrow \frac{100\ +\ x}{100\ -\ x}\ =\ \frac{2}{1}$
$\Rightarrow (100+x) =(200-2x)$
$\therefore x = \frac{100}{3}\% = 33\tfrac{1}{3}\%$
Hence, the correct answer is $33\tfrac{1}{3}\%$.

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