The population ratio of higher to lower energy level is 1.059 * 10 power -30. Find the wavelength of light emitted at 330K. Answer each step...
the ratio of population of two energy levels is 1.059 find the wavelength of light emitted by spontaneous emission at 330k
the ratio of population of two energy levels is 1.059 find the wavelength of light emitted by spontaneous emission at 330k
Dear Aspirant,
We know that, N2/N1= population ratio = 1.059*10^-30 & T=330K, similarly we are supposed to find lambda(wavelength)
Also,
N2/N1 = e^(-E/K*T)
Taking log on Both sides,
Log(N2/N1) = -E/K*T = [(-h*rho)/(K*T)]
rho = c/lambda
So, after rearranging we get,
Log (N2/N1) = {(-h*c)/(K) * (1/lambda*T)} after solving this through logarithmic functions, you will get the answer of lambda = 632.8mm
Kindly understand the answer by solving by your own too. Hope it helps you.
Thanks.
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