Question : The present population of the town is 26010. It increases annually at a rate of 2%. What was the population of the town two years ago?
Option 1: 25000
Option 2: 25100
Option 3: 25200
Option 4: 25500
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Correct Answer: 25000
Solution : The present population is $26010$. The population after $n$ years = $P(1+\frac{r}{100})^n$, where $P$ is the population before two years and the population increases at a rate of $r$% per annum. So, $P(1+\frac{2}{100})^2 = 26010$ ⇒ $P = 25000$ Hence, the correct answer is 25000.
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Question : The number of trees in a town is 17640. If the number of trees increases annually at a rate of 5%, how many trees were there two years ago?
Option 1: 14000
Option 2: 15000
Option 3: 16000
Option 4: 19450
Question : Direction: The age of the father 4 years ago was 8 times the age of his son. At present, the father's age is 4 times that of his son. Find the present age of son.
Option 1: 9 years
Option 2: 7 years
Option 3: 14 years
Option 4: 18 years
Question : The sum of the ages of the mother and her daughter is 60 years. 12 years ago, the mother was eight times as old as her daughter. How old is the daughter at present?
Option 1: 20 years
Option 2: 28 years
Option 3: 16 years
Option 4: 12 years
Question : The population of the city is 20,000. It increases by 20% during the first year and 30% during the second year. The population after two years will be:
Option 1: 32,000
Option 2: 40,000
Option 3: 31,200
Option 4: 30,000
Question : Directions: The present age of A is two times the present age of B. After 8 years, B's age will be four times C's present age. If 9 years ago, C celebrated his fifth birthday, then what is the present age (in years) of A?
Option 1: 88
Option 2: 96
Option 3: 92
Option 4: 84
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