Question : The product of the two numbers is 1500 and their HCF is 10. The number of such possible pairs is/are:
Option 1: 1
Option 2: 3
Option 3: 4
Option 4: 2
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Correct Answer: 2
Solution : Given: The product of the two numbers is 1500 and their HCF is 10. Let the two numbers be $10x$ and $10y$ So, $10x×10y=1500$ ⇒ $100xy=1500$ ⇒ $xy=15$ Now, 15 = 15 × 1 and 15 = 3 × 5 Therefore, the possible number of pairs which are co-prime to each other is 2. Hence, the correct answer is 2.
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Question : The sum of two positive numbers is 240 and their HCF is 15. Find the number of pairs of numbers satisfying the given condition.
Question : The product of two two-digit numbers is 2160, and their HCF is 12. The numbers are:
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Question : Two numbers are in the ratio of 6 : 5. If their HCF is 3, then what is the LCM of the two numbers?
Question : The HCF and LCM of the two numbers are 21 and 84, respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is:
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