Question : The radius of a circle is 5 cm and the length of one of its chords is 8 cm. Find the distance of the chord from the centre.
Option 1: 3 cm
Option 2: 4 cm
Option 3: 5 cm
Option 4: 2 cm
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 3 cm
Solution :
Radius of circle with centre $O$ is $OB$ = $5$ cm
Length of chord $AB = 8$ cm
We know that perpendicular from the centre to the chord bisects the chord.
So, $OD \perp AB$ which bisects $AB$ at $D$.
∴ $AD=DB=4$ cm
In $\Delta OBD$,
$OB^2=OD^2+BD^2$ (Pythagoras theorem)
⇒ $(5)^2=OD^2+(4)^2$
⇒ $OD=3$
Hence, the correct answer is 3 cm.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
