Question : The radius of a circle is 5 cm. The length of chord AB in this circle is 6 cm. What is the distance of this chord from the centre of the circle?
Option 1: 4 cm
Option 2: 5 cm
Option 3: 6 cm
Option 4: 8 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 4 cm
Solution :
Let $OB$ be the radius of the circle and $OD$ be the distance from the centre to the chord $AB$.
The radius of a circle, $OB$ = 5 cm
Length of chord $AB$ = 6 cm
Now, we know altitude from the centre of a circle to its chord bisects the chord.
So, $BD$ = 3 cm
Applying Pythagoras theorem, we get:
$OB^2=BD^2+OD^2$
⇒ $5^2=3^2+OD^2$
$\therefore OD=4$ cm
Hence, the correct answer is 4 cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
