Question : The radius of a hemisphere is twice that of a sphere. What is the ratio of the total surface area of the hemisphere and sphere?
Option 1: 3 : 1
Option 2: 12 : 1
Option 3: 4 : 1
Option 4: 6 : 1
Correct Answer: 3 : 1
Solution : The total surface area of a sphere with radius r, $⇒\text{TSA}_1 = 4\pi r^2$ The total surface area of a hemisphere with radius R, $⇒\text{TSA}_2 = 3\pi R^2$ Given that the radius of the hemisphere is twice that of the sphere, ($R = 2r$). $⇒\text{TSA}_2 = 3\pi (2r)^2 = 12\pi r^2$ The ratio of the total surface area of the hemisphere to the sphere. $⇒\frac{\text{TSA}_2}{\text{TSA}_1} = \frac{12\pi r^2}{4\pi r^2} = 3$ Hence, the correct answer is 3 : 1.
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Question : The radius of circle A is twice that of circle B and the radius of circle B is twice that of circle C. Their area will be in the ratio:
Option 1: 16 : 4 : 1
Option 2: 4 : 2 : 1
Option 3: 1 : 2 : 4
Option 4: 1 : 4 : 16
Question : The ratio of the total surface area and volume of a sphere is 2 : 7. Its radius is:
Option 1: 7.5 cm
Option 2: 10.5 cm
Option 3: 10 cm
Option 4: 7 cm
Question : A sphere and another solid hemisphere have the same surface area. The ratio of their volumes is:
Option 1: $2 \sqrt{3}: 8$
Option 2: $3 \sqrt{3}: 8$
Option 3: $3 \sqrt{3}: 4$
Option 4: $\sqrt{3}: 4$
Question : The ratio of the curved surface area of two cones is 1 : 4 and the ratio of slant height of the two cones is 2 : 1. What is the ratio of the radius of the two cones?
Option 1: 1 : 2
Option 2: 1 : 4
Option 3: 1 : 8
Option 4: 1 : 1
Question : If the radius of a sphere increases by 10%, what would be the change in the surface area of the sphere?
Option 1: 20%
Option 2: 21%
Option 3: 31%
Option 4: 25%
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