Question : The radius of the base of a cylinder is 14 cm and its volume is 6160 cm3. The curved surface area (in cm2) is: (Take $\pi=\frac{22}{7}$)
Option 1: 778
Option 2: 880
Option 3: 660
Option 4: 940
Correct Answer: 880
Solution :
The volume of a cylinder, $V = \pi r^2 h$, where $r$ is the radius and $h$ is the height.
⇒ $h = \frac{V}{\pi r^2}$
Given that $V = 6160 \, \text{cm}^3$, $r = 14 \, \text{cm}$, and $\pi = \frac{22}{7}$
$\therefore h = \frac{6160}{\frac{22}{7} \times 14^2} = 10 \, \text{cm}$
The curved surface area (CSA) of a cylinder
$= 2\pi rh$
$= 2 \times \frac{22}{7} \times 14 \times 10 = 880 \, \text{cm}^2$
Hence, the correct answer is 880.
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