Question : The radius of the base of a cylinder is 14 cm and its volume is 6160 cm3. The curved surface area (in cm2) is: (Take $\pi=\frac{22}{7}$)
Option 1: 778
Option 2: 880
Option 3: 660
Option 4: 940
Correct Answer: 880
Solution : The volume of a cylinder, $V = \pi r^2 h$, where $r$ is the radius and $h$ is the height. ⇒ $h = \frac{V}{\pi r^2}$ Given that $V = 6160 \, \text{cm}^3$, $r = 14 \, \text{cm}$, and $\pi = \frac{22}{7}$ $\therefore h = \frac{6160}{\frac{22}{7} \times 14^2} = 10 \, \text{cm}$ The curved surface area (CSA) of a cylinder $= 2\pi rh$ $= 2 \times \frac{22}{7} \times 14 \times 10 = 880 \, \text{cm}^2$ Hence, the correct answer is 880.
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