Question : The radius of the base of a right circular cone is 5 cm. Its slant height is 13 cm. What is its volume (in cm3, rounded off to 1 decimal place)? (Take $\pi=\frac{22}{7}$)
Option 1: 328.6
Option 2: 323.4
Option 3: 314.3
Option 4: 340.5
Correct Answer: 314.3
Solution :
Given: Radius = 5 cm
Slant height = 13 cm
$\text{height}=\sqrt{\text{slant height}^2-\text{radius}^2}=\sqrt{13^2-5^2}=\sqrt{169-25}=\sqrt{144}=12$
We know that,
The volume of the cone
= $\frac{1}{3}\pi r^2h$
= $\frac{1}{3}\times\frac{22}{7}\times 5 \times 5 \times 12$
= $\frac{2200}{7}$
= $314.3$ cm
3
Hence, the correct answer is 314.3.
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