the radius of the Bohr orbit in the ground state of hydrogen atom is 0.5 angstrom. the radius of the orbit of the electron in the third excited state of He+ will be
Answer (1)
11th Jan, 2020
Hello!!
formula for Bohr'so radius is 0.59×n^2/z,where n is the number of orbit or the principal quantum number and z is the atomic number of atom,for He atomic number is 2 and since you are asking about 3rd orbit it would become, 0.5×(3)^2/2=2.25.
Thanks
Comments (0)
Related Questions
Trending Articles/News
