Question : The radius of the incircle of an equilateral $\Delta$ ABC of side $2\sqrt{3}$ cm is $x$ cm. The value of $x$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{2}$
Option 3: $1$
Option 4: $\sqrt{3}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: $1$
Solution :
The radius of the incircle of an equilateral triangle is given by the formula $r = \frac{a}{2\sqrt{3}}$, where $a$ is the side length of the triangle.
Given that the length of the sides of the equilateral triangle ABC is $2\sqrt{3}$ cm.
$x = \frac{2\sqrt{3}}{2\sqrt{3}} = 1$
Hence, the correct answer is 1 cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
