The ratio of closed packed atoms to tetrahedral holes in cubic close packing is
Answer (1)
6th Apr, 2018
It's 1:2 ratio.
Every constituent has two tetrahedral voids.
In CCP lattice atoms = (1/8
×
8)
+(
6
×1/2)
=
1
+
3
=
4
∴
T
e
t
r
a
h
e
d
r
a
l
V
o
i
d
=
4
×
2
=
8
Thus ratio = 4:8 :: 1:2
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