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The ratio of closed packed atoms to tetrahedral holes in cubic close packing is


Rakshithn 6th Apr, 2018
Answer (1)
AKHILA SRI 6th Apr, 2018
It's 1:2 ratio.
Every constituent has two tetrahedral voids.
In CCP lattice atoms = (1/8 × 8) +( 6 ×1/2)
= 1 + 3
= 4
T e t r a h e d r a l V o i d = 4 × 2
= 8
Thus ratio = 4:8 :: 1:2

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