Question : The remainder of the term $9+9^2+\ldots+9^{(2 n+1)}$ when divided by 6 is:
Option 1: 1
Option 2: 4
Option 3: 2
Option 4: 3
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : Given, $9+9^2+\ldots+9^{(2 n+1)}$ is divided by 6 Consider, $9+9^2+\ldots+9^{(2 n+1)}$ Here, for each term in the series, the remainder when divided by 6 is 3. The sum of the remainder of each term = 3 + 3 + 3 + ............+ up to 2n + 1 terms 2n + 1 is an odd number, so when the sum of an odd number times 3 is divided by 6, the remainder is 3. Hence, the correct answer is 3.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : A positive integer, when divided by 425, gives a remainder of 45. When the same number is divided by 17, the remainder will be:
Question : What is the remainder when $3^8$ is divided by 7?
Question : A number when divided by 78 gives the quotient 280 and the remainder 0. If the same number is divided by 65, what will be the value of the remainder?
Question : A number x, when divided by 289, leaves 18 as the remainder. The same number when divided by 17 leaves y as a remainder. The value of y is:
Question : If 7 divides the integer n, then the remainder is 2. What will be the remainder if 9n is divided by 7?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile