Question : The side of an equilateral triangle is $12 \text{ cm}$. What is the area (in $\text{cm}^2$, rounded off to 2 decimal places) of the triangle? (Given $\sqrt{3} = 1.732$)
Option 1: 68.07
Option 2: 63.89
Option 3: 62.35
Option 4: 65.23
Correct Answer: 62.35
Solution :
Given: The side of an equilateral triangle is $12 \text{ cm}$.
Area of the equilateral triangle:
$=\frac{\sqrt{3}}{4} × (\text{side})^{2}$
$=\frac{\sqrt{3}}{4} × 12^{2}$
$=\frac{\sqrt{3}}{4} × 144$
$=\sqrt{3} × 36$
$= 1.732 × 36 $
$= 62.35 \text{ cm}^2$
Hence, the correct answer is 62.35.
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