Question : The sides of a triangle are in the ratio 7 : 9 : 12. The difference between the lengths of the largest and smallest sides is 15 cm. The length of the largest side would be (in cm):
Option 1: 36
Option 2: 12
Option 3: 60
Option 4: 24
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 36
Solution : Given: The sides of a triangle are in the ratio of 7 : 9 : 12. Let the sides of the triangle be $7x, 9x$, and $12x$. According to the question, $12x -7x = 15$ ⇒ $5x = 15$ ⇒ $x = \frac{15}{5} = 3$ Largest side $=12x = 12 × 3= 36$ cm Hence, the correct answer is 36.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The lengths of the two sides of a triangle are 14 cm and 9 cm. Which of the options below can be the length of the third side?
Question : The median of an equilateral triangle is $15 \sqrt{3} \mathrm{~cm}$. What is the side of this triangle?
Question : The lengths of the two sides adjacent to the right angle of a right-angled triangle are 1.6 cm and 6.3 cm. Find the length of the hypotenuse.
Question : The radius of the incircle of a triangle whose sides are 9 cm, 12 cm, and 15 cm is:
Question : The sides of a triangle are of length 8 cm, 15 cm, and 17 cm. Find the area of the triangle.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile