Question : The sides of a triangle are of length 8 cm, 15 cm, and 17 cm. Find the area of the triangle.
Option 1: 65 cm2
Option 2: 75 cm2
Option 3: 60 cm2
Option 4: 70 cm2
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 60 cm 2
Solution :
The sides are 8 cm, 17 cm, and 15 cm.
Let $a=8,b=17,$ and $c=15$
Semi perimeter, $s=\frac{a+b+c}{2}=\frac{8+17+15}{2}=20$
Area of the triangle by Heron's Formula,
Area of the triangle $= \sqrt{s(s−a)(s−b)(s−c)}$
⇒ Area of the triangle $= \sqrt{20(20−8)(20−17)(20−15)}$
⇒ Area of the triangle $= \sqrt{20 \times 12 \times 3\times 5}$
⇒ Area of the triangle $= 4 \times 5 \times 3$
$\therefore$ Area of the triangle $= 60$ cm
2
Hence, the correct answer is 60 cm
2
.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.