Question : The sides of similar triangle $\triangle ABC$ and $\triangle DEF$ are in the ratio of $\frac{\sqrt{3}}{\sqrt{5}}$. If the area of $\triangle ABC$ is $90 \text{ cm}^2$, then the area of $\triangle DFF\left(\right.$ in $\left.\text{cm}^2\right)$ is:
Option 1: 150
Option 2: 152
Option 3: 154
Option 4: 156
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 150
Solution : Ratio of their sides = $\frac{\sqrt3}{\sqrt5}$ $\therefore$ Ratio of their areas = $(\frac{\sqrt3}{\sqrt5})^2 = \frac{3}{5}$ Given the area of $\triangle ABC$ = $90\text{ cm}^2$ $\therefore$ Area of $\triangle DEF=90\times \frac{5}{3} = 150\text{ cm}^2$ Hence, the correct answer is 150.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : $ABC$ is a right-angled triangle, right-angled at B and $\angle A=60°$ and $AB=20$ cm, then the ratio of sides $BC$ and $CA$ is:
Question : The sides of a triangle are 9 cm, 6 cm, and 5 cm. What is the value of the circumradius of this triangle?
Question : The sides of a triangle are 20 cm, 21 cm, and 29 cm. The area of the triangle formed by joining the midpoints of the sides of the triangle will be:
Question : If $\triangle ABC$~$\triangle PQR$, the ratio of perimeter of $\triangle ABC$ to perimeter of $\triangle PQR$ is 36 : 23 and QR = 3.8 cm, then the length of BC is:
Question : Find the area of an equilateral triangle whose sides are 12 cm.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile