Question : The six-digit number $\mathrm{N = 4a6b9c}$ is divisible by $99$, then the maximum sum of the digits of $\mathrm{N}$ is:
Option 1: 18
Option 2: 36
Option 3: 45
Option 4: 27
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 27
Solution : We have, the six-digit number $\mathrm{N = 4a6b9c}$ is divisible by $99$. Divisibility rule for $9$, A number is divisible by $9$ if the sum of digits is divisible by $9$. As $\mathrm{N = 4a6b9c}$ is divisible by $9$. The sum of the digits $=\mathrm{(4+a+6+b+9+c)}$ The sum of the digits $=\mathrm{(19+a+b+c)}$ $\mathrm{(19+a+b+c)}$ is divisible by $9$ _________(i) Divisibility rule for $11$, A number is divisible by $11$ if the difference between the sum of the digits at even places and the sum of the digits at odd places is divisible by $11$. As $\mathrm{N = 4a6b9c}$ is divisible by $11$. $\mathrm{(4+6+9)-(a+b+c)}$ is divisible by $11$ $\mathrm{19-(a+b+c)}$ is divisible by $11$ _________(ii) From the equation (i) and (ii), $\mathrm{(a+b+c)=8}$ The maximum sum of the digits $=19+(a+b+c)=19+8=27$ Hence, the correct answer is $27$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : By interchanging the digits of a two-digit number, we get a number which is four times the original number minus 24. If the digit at the unit's place of the original number exceeds its digit at ten's place by 7, then the original number is:
Question : What will be the greatest number $32 \mathrm{a} 78\mathrm{b}$, which is divisible by 3 but NOT divisible by 9? (Where a and b are single digit numbers).
Question : The product of the digits of a two-digit number is 24. If we add 45 to the number, the new number obtained is a number formed by interchanging the digits. What is the original number?
Question : The product of the digits of a 2-digit number is 24. If we add 45 to the number, the new number obtained is a number formed by interchanging the digits. What is the original number?
Question : If $\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)^2=9$, then what is the value of $\mathrm{k}^3+\frac{1}{\mathrm{k}^3} ?$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile